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TALENT of the YEAR 2022

  Форум / Всё о iStripper

celine
TEAM
Присоединился в Sep 2007

1876 Сообщения
27 December 2022
It's time to choose the iStripper Talent of the Year 2022, among the 12 Talents of the month 2022!

A. Alissa Foxy (Talent of January 2022)


B. Sia Siberia (Talent of February 2022)


C. Sybil (Talent of March 2022)


D. Anna Delos (Talent of April 2022)


E. Mina von D (Talent of May 2022)


F. Kitty (Talent of June 2022)


G. Melody Marks (Talent of July 2022)


H. Sofi Vega (Talent of August 2022)


I. Freya Mayer (Talent of September 2022)


J. Josephine Jackson (Talent of October 2022)


K. Yenifer Chacon (Talent of November 2022)


L. Milena Ray (Talent of December 2022)



HOW TO PARTICIPATE?

Go to Discord https://discord.gg/kwrqw3Xy and click on the letter that corresponds to your favorite Talent.

The Poll will end on January 2, 2023.


Additional question:

name ONE model not in this list that you would have elected model of the year 2022
HanzoMain
Присоединился в May 2019

2 Сообщения
27 December 2022
Kelly Collins!
Jaipee
Присоединился в Jan 2022

47 Сообщения
27 December 2022
No Discord, and won't never/use have it...

I would have voted for A. Alissa Foxy though.
And for the 2nd part, even if I can't vote but others can, it would have been nice to have also the full list of models in 2022 (not in the main list), for simplifying the research and selection process... ;)
zzmaskers
Присоединился в Mar 2011

608 Сообщения
27 December 2022
Kelly Collins!
For me also, but will be the one for 2023, because I suppose her to be a Talent of the Month in in 2023.
Ullubu
Присоединился в Dec 2011

746 Сообщения
27 December 2022
And for the 2nd part, even if I can't vote but others can, it would have been nice to have also the full list of models in 2022 (not in the main list), for simplifying the research and selection process... ;)

Set the app filters to 2022 and sort by name.
celine
TEAM
Присоединился в Sep 2007

1876 Сообщения
27 December 2022 (edited)
@Jaipee, shame, discord is a nice place to be, with friendly and helpful people....

BTW, here is the tend after a few minutes

C 21
G 10
A 40
B 22
I 21
F 12
E 6
D 4
J 14
L 7
K 3
H 1
celine
TEAM
Присоединился в Sep 2007

1876 Сообщения
27 December 2022
We definitely miss Kelly Collins in this list yes ! But you are right, she's a favorite for the coming Talent of the Month 😍
pickle1
MODERATOR
Присоединился в Mar 2019

1353 Сообщения
27 December 2022
My top model has to have been Clemence Audiard😍
nickassassin
Присоединился в Nov 2022

1 Сообщения
27 December 2022
the invention link of discord dosent work for me
R2D34ever2
Присоединился в Dec 2007

351 Сообщения
27 December 2022
no need to vote for me ..76 votes alyssa ... winner !
ADMIRERZ
Присоединился в Jun 2008

207 Сообщения
27 December 2022
I don't have discord on this tablet. Someone vote for me randomly . Either Milena, Alisa or Freya.
Djoal
Присоединился в Sep 2018

49 Сообщения
27 December 2022
same Alissa, Freya or Milena any of them 3 will be good for me.
Jaipee
Присоединился в Jan 2022

47 Сообщения
27 December 2022
(...)
Set the app filters to 2022 and sort by name.
??
I only use the PC version and there is no year filter in the client [1.2.360/32bits/Qt 5.12.3], and I guess you refer to a smartphone application and its features...
So then the list is really needed for all, and the simplest solution, independant from any platform, is to have the list set out in this forum...
Evaneself
Присоединился в Dec 2019

332 Сообщения
27 December 2022
Alissa Foxy is the winner? 🔥 Wow!!!
TheEmu
Присоединился в Jul 2012

3309 Сообщения
27 December 2022 (edited)
I only use the PC version and there is no year filter in the client [1.2.360/32bits/Qt 5.12.3],

Strange, I used that "non-existant" filter only a few minutes ago. Its called "Release Date".
Socialhazard
Присоединился в Nov 2020

1150 Сообщения
27 December 2022
@Evaneself

Not yet but one hell of a lead. 😄 😎
Stanston
Присоединился в Aug 2018

1012 Сообщения
27 December 2022
So then the list is really needed for all, and the simplest solution, independant from any platform,
is to have the list set out in this forum...
https://www.istripper.com/de/forum/thread/50493/1?post=754682
Всё о iStripper / Talent Of The Month - the full list
https://docs.google.com/spreadsheets/d/13hK_Q4DQ-XwvrRqpljOTl_A6dePv9sVZV4DRJMzWgq8/edit#gid=0
Evaneself
Присоединился в Dec 2019

332 Сообщения
27 December 2022
From this list, the most beautiful models for me are Freya Mayer, Sybil, Sia Siberia, Alissa Foxy & Milena Ray.
Maybe the models Freya Mayer, Sybil & Milena Ray would be the First Place.
I'm not sure. 😭
JonC001
Присоединился в Mar 2008

1508 Сообщения
27 December 2022
What is the point in users voting here on istripper?
The real voting is at discord. Not everyone can/will go there.
However, there are no real voting options here.
pickle1
MODERATOR
Присоединился в Mar 2019

1353 Сообщения
27 December 2022
People are free to voice their opinions here - but if they want their vote to count, then it takes place on Discord.
JonC001
Присоединился в Mar 2008

1508 Сообщения
27 December 2022
👌
Evaneself
Присоединился в Dec 2019

332 Сообщения
27 December 2022 (edited)
Until now, the votes:
1. Alissa Foxy
2. Freya Mayer
3. Sia Siberia

Good thing we don't like the same girls, so that we don't fight each other. 😎
JonC001
Присоединился в Mar 2008

1508 Сообщения
27 December 2022
I voted a while back.
I clicked the 'c' because it was the first letter in that emoji list. And Alissa Foxy is first in that list.
Later, I looked again and realized that Alissa is 'a'.
But 'a' is not first. So I changed my vote. I definitely want Alissa to win.
Evaneself
Присоединился в Dec 2019

332 Сообщения
27 December 2022 (edited)

Freya Mayer, you have perfect beauty! The world does not recognize the art of sculpture in your body! 💖
JonC001
Присоединился в Mar 2008

1508 Сообщения
27 December 2022
@Evaneself said this:
Freya Mayer, you have perfect beauty!
I totally agree. Freya is perfect. But there can be only one winner. (if two were possible, Freya would be another choice for me.)
Philours
Присоединился в Feb 2019

1612 Сообщения
27 December 2022 (edited)
I totally agree. Freya is perfect. But there can be only one winner. (if two were possible, Freya would be another choice for me.)
Mais non, @JonC001, rien n'interdit qu'il y ai ex-aequo, il me semble😊
But no @JonC001 , , nothing prohibits a tie, it seems to me😊

Si vous passez votre souris sur les différentes lettres, vous vous apercevrez que certains n'ont pas hésiter a voter pour plusieurs candidates, contrairement aux recommandations de Céline. Alors, pourquoi ne feriez vous pas de même ?

If you pass your mouse over the different letters, you will notice that some did not hesitate to vote for several candidates, contrary to Céline's recommendations. So why don't you do the same? 😊
Zawan
Присоединился в Sep 2020

101 Сообщения
27 December 2022
Additional question:

name ONE model not in this list that you would have elected model of the year 2022
Sonya Blaze again 😄🔥!
Evaneself
Присоединился в Dec 2019

332 Сообщения
27 December 2022
If you pass your mouse over the different letters, you will notice that some did not hesitate to vote for several candidates, contrary to Céline's recommendations.

How to choose just one?
It's good enough that we can only vote only once a model.
JonC001
Присоединился в Mar 2008

1508 Сообщения
27 December 2022 (edited)
@Philours said this:
If you pass your mouse over the different letters, you will notice that some did not hesitate to vote for several candidates, contrary to Céline's recommendations. So why don't you do the same? 😊
Yes. Last year I first voted for four girls. Somewhat later I dropped two of them and kept two.
Those were 1 Little Caprice and 2 Sonya Blaze. I am happy that Sonya won even though I was (just a bit more) preferring Caprice. Last year, I liked all of the girls.
This year I will vote for just one. And Alissa Foxy far surpasses the other girls, three of whom I do not like.
BedreVita
Присоединился в Feb 2021

43 Сообщения
27 December 2022
There is no doubt; Belka is the talent of the year

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